What is Integration?
Integration is a foundational concept in calculus that serves as the inverse operation to differentiation. While differentiation determines the rate of change at a given point, integration accumulates these values to calculate total sizes, most notably the net area bounded under a curve.
- Indefinite Integrals: Represent families of functions and always include an arbitrary constant (C).
- Definite Integrals: Evaluated across specific physical intervals to provide a concrete numeric value.
1. The Power Rule
Used to integrate variable bases raised to fixed numerical exponents.
∫ xn dx = (xn+1 / (n + 1)) + C (where n ≠ -1)
Question 1.1: Find the indefinite integral: ∫ x4 dx.
- A) 4x3 + C
- B) (1/5)x5 + C
- C) 5x5 + C
- D) x5 + C
Correct Answer: B
Solution: Raise power by 1 and divide by the new exponent: (4+1=5). Result =
(1/5)x5 + C.
Question 1.2: Evaluate: ∫ 1/x3 dx.
- A) -1/(2x2) + C
- B) 1/(4x4) + C
- C) -3/x4 + C
- D) log(x3) + C
Correct Answer: A
Solution: Rewrite as negative exponent: ∫ x
-3 dx. Apply rule: x
-2 / -2 + C =
-1/(2x2) + C.
2. Constant & Constant Multiple Rule
Constants can be factored directly out of integration operations cleanly.
∫ k dx = kx + C | ∫ k·f(x) dx = k ∫ f(x) dx
Question 2.1: Find ∫ 7 dx.
- A) 7 + C
- B) 0 + C
- C) 7x + C
- D) 7/2 x2 + C
Correct Answer: C
Solution: The integral of any standalone constant
k with respect to x is always
kx + C. Thus,
7x + C.
Question 2.2: Evaluate ∫ 6x2 dx.
- A) 2x3 + C
- B) 18x3 + C
- C) 6x3 + C
- D) 3x2 + C
Correct Answer: A
Solution: Factor out 6: 6 ∫ x
2 dx = 6 · (x
3 / 3) =
2x3 + C.
3. Sum and Difference Rule
Integrals can be distributed cleanly across independent additive or subtractive elements.
∫ [f(x) ± g(x)] dx = ∫ f(x) dx ± ∫ g(x) dx
Question 3.1: Evaluate ∫ (3x2 + 2x) dx.
- A) 6x + 2 + C
- B) x3 + x2 + C
- C) 3x3 + 2x2 + C
- D) x3 + 2x + C
Correct Answer: B
Solution: Split terms: ∫ 3x
2 dx + ∫ 2x dx = x
3 + x
2 + C. Result =
x3 + x2 + C.
Question 3.2: Find ∫ (5 - x) dx.
- A) 5x - (1/2)x2 + C
- B) 5x - x + C
- C) -1 + C
- D) 5x - x2 + C
Correct Answer: A
Solution: Integrating independent blocks gives: ∫ 5 dx - ∫ x dx =
5x - (1/2)x2 + C.
4. The Exponential Rule
Natural exponential operations are unique as they serve as their own primary integrals.
∫ ex dx = ex + C | ∫ eax dx = (1/a)eax + C
Question 4.1: Evaluate ∫ 4ex dx.
- A) ex + C
- B) 4ex + C
- C) 2e2x + C
- D) 4xex-1 + C
Correct Answer: B
Solution: Pull out the constant scale factor directly: 4 ∫ e
x dx =
4ex + C.
Question 4.2: Find ∫ e5x dx.
- A) 5e5x + C
- B) e5x + C
- C) (1/5)e5x + C
- D) e6x/6 + C
Correct Answer: C
Solution: Divide structural expression by the internal derivative coefficient (5):
(1/5)e5x + C.
5. The Reciprocal Rule (Logarithmic Rule)
The solution when evaluating functions with a power profile of exactly -1.
∫ (1/x) dx = ln|x| + C
Question 5.1: Find the integral: ∫ 3/x dx.
- A) -3/x2 + C
- B) 3 ln|x| + C
- C) ln|3x| + C
- D) 3x0 + C
Correct Answer: B
Solution: Separate the numerator value: 3 ∫ (1/x) dx =
3 ln|x| + C.
Question 5.2: Evaluate ∫ 1/(4x) dx.
- A) (1/4) ln|x| + C
- B) ln|4x| + C
- C) 4 ln|x| + C
- D) -1/(16x2) + C
Correct Answer: A
Solution: Extract scalar fractions cleanly before processing: (1/4) ∫ (1/x) dx =
(1/4) ln|x| + C.
6. Trigonometric Rules (Sine and Cosine)
Core cyclic rules tracking foundational derivatives in inverse format.
∫ sin(x) dx = -cos(x) + C | ∫ cos(x) dx = sin(x) + C
Question 6.1: Evaluate ∫ -2 cos(x) dx.
- A) 2 sin(x) + C
- B) -2 sin(x) + C
- C) -2 cos(x) + C
- D) 2 cos(x) + C
Correct Answer: B
Solution: The integral of cos(x) is sin(x). Multiplying by -2 yields
-2 sin(x) + C.
Question 6.2: Find ∫ (x - sin(x)) dx.
- A) (1/2)x2 - cos(x) + C
- B) x2 + cos(x) + C
- C) (1/2)x2 + cos(x) + C
- D) 1 - cos(x) + C
Correct Answer: C
Solution: ∫ x dx - ∫ sin(x) dx = (1/2)x
2 - (-cos(x)) + C =
(1/2)x2 + cos(x) + C.
7. Advanced Trigonometric Rules (Secant Squared)
Since the derivative of tangent functions equals secant squared, integration reverses this track perfectly.
∫ sec2(x) dx = tan(x) + C
Question 7.1: Evaluate ∫ 5 sec2(x) dx.
- A) 5 tan(x) + C
- B) -5 tan(x) + C
- C) 5 sec(x) + C
- D) 5/3 sec3(x) + C
Correct Answer: A
Solution: Factor out the scale parameter: 5 ∫ sec
2(x) dx =
5 tan(x) + C.
Question 7.2: Find ∫ sec2(2x) dx.
- A) tan(2x) + C
- B) 2 tan(2x) + C
- C) (1/2) tan(2x) + C
- D) sec(2x) tan(2x) + C
Correct Answer: C
Solution: Divide by the internal linear derivative coefficient (2) to scale back the transformation:
(1/2) tan(2x) + C.
8. Integration by Substitution (u-Substitution)
The inverse version of the Chain Rule. Used when an expression contains both an inner function and its derivative.
∫ f(g(x))·g'(x) dx = ∫ f(u) du, where u = g(x)
Question 8.1: Evaluate ∫ 2x ex2 dx.
- A) ex2 + C
- B) 2ex2 + C
- C) x2ex + C
- D) ex + C
Correct Answer: A
Solution: Set
u = x2, giving
du = 2x dx. Substituting gives ∫ e
u du = e
u + C =
ex2 + C.
Question 8.2: Find ∫ (2x + 3)5 dx.
- A) (2x + 3)6 / 6 + C
- B) (2x + 3)6 / 12 + C
- C) 2(2x + 3)6 + C
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